Projection of Points – Point’s position will be given in data. We need to find out its projection on H.P. (Horizontal Plane) and on V.P. (Vertical Plane).

There are maximum four quadrant wise positions possible of point. As we all know about quadrant, there are 4 quadrants exist. See figure below.

Here are four quadrant wise positions for any point.

- Above H.P. and In Front of V.P. which shows point is in First Quadrant
- Above H.P. and Behind V.P. which shows point is in Second Quadrant
- Below H.P. and Behind V.P. which shows point is in Third Quadrant
- Below H.P. and In Front of V.P. which shows point is in Fourth Quadrant

See figure below.

Let us check these quadrants in H.P. (Horizontal Plane) and on V.P. (Vertical Plane) view. See figure below.

*To find solution of problems based on projections we need to rotate H.P. (Horizontal Plane) in clockwise direction to 90º.*

After this rotation of H.P. it will become parallel to V.P. See fig below.

**Solved Example:**

**Data: A Point “M” is 40 mm above H.P. and 40 mm in front of V.P. Draw its projections.**

**Solution:** As point’s position is above H.P. and In Front of V.P. it is in First Quadrant. See figure below.

We will get m’ projected on V.P. for front view which shows Elevation and m on H.P. for top view which shows Plan.

So, plan will be 40 mm in front of V.P. and Elevation will be 40 mm above H.P.

As per we discussed before for solution we need to rotate H.P. in clockwise direction up to 90º. See figure below.

So the solution for the above data is:

*Plan: Projection on H.P. **Elevation: Projection on V.P.*

In same way we can find projections for any point at any condition. Just remember to rotate H.P. at 90º while drawing solution.

**Here are few important notes:**

- When point is in 1
^{st}quadrant, its plan will be below XY (reference line) and elevation will be above XY. - When point is in 2
^{nd}quadrant, its plan and elevation both will be above XY. - When point is in 3
^{rd}quadrant, its plan will be above XY and elevation will be below XY. - When point is in 4
^{th}quadrant, its plan and elevation both will be below XY.

Thanks bro it really gave me a start

Always welcome…!

really really helpful…my teacher in dtu is really horrible…

Thank you very much for appreciation!

God Bless you.

Sir,

So help full ……

Thanks a lot

with regards

Stephen

Thank you very much for appreciation!

God Bless you.

Thanks you very much for making this website ..

Thanks for appreciation & welcome !

Very Helpful….. i was trying to find notes in pdf…… But now i've got this site,no need of notes now…….. Thanks Sir……

Really appreciate this….many thanks!

Thank You very much Sir I understood it perfectly

My teacher is really horrible and babbles whenever he teaches ED

This really helped me a lot

Thanks for appreciation!

if both the views of a point coincides on the reference line then point lies which angle

Point lies on reference line itself. And default quadrant considered as first.

thanks a lot bro….best site ever….:)

btw is the portion same for

mumbai universitytoo…???Thanks dear….and yes almost same for Mumbai university!

thank you dear. these are what we tought this night.

welcome dear!

Why we rotating object by 90 deg clockwise

If we dont rotate clockwise direction then we cant see the top view from front direction as we are drawing our solution by keeping front view as default view.

hey………it's very delightful one………….juzt delighted……..:p

thanks sir

This was really helpful, thank you.

Comment…very very helpful information and this is basic knowledge of projection of points.

Thank You!

its very use ful

sir,

its so helpfull

really now am perfect in projection of points

Very useful…thank you. So much

i cant understand a bit about that rotation thing in the class but in here,it was great i got it in the first time itself thank u for this website

i want remaining problems solutions in projection of points

thanku so much sir it;s really very good explanation for drawing fundamentals

Thank u so much sir,this help me clear my dougths.

Thanking u sir,for introdusing such an awesome site.

Very much helpfulll…..

May God blesss everyone behind this great venture…….

Thank you and all above who appreciated our work.

Very very useful… Ty for introducing such an awesome site… Is this available for other subjects like physics also??

Dear, No its available only for Engineering Drawing 🙂

thank u very much.this website

clear my all doult

Thankyou Sir…

Its Awesome….:)

Awesome site

thanks

sir,

it’s very easy to analyze…

and easy to understand…..

thank you very much

thnks a lot siR

it is so helpful sir thank u….sir

thank u sir .. god bless u !!

what is aligment in the drwaing

It's really awesome…..sirThanks for thisreally helped me alot

Thank you sir for this ammazing website…it really helps me a lot…

it was really helpful THANKS ALOT 🙂 🙂

Very helpful..Thanks a lot.

you make it very easy to understand..

Oh My God…….Very helpful site actually pulled me out of pile of confused drawing

Very grateful to you Sir for introducing this site 😀

Always Pleasure 🙂

Nice work sir really helpfull please be continue

was really useful thanks

thanks it made me completly underatand which taught by my sir

Very very use full thanks a lot

beautiful sir

What if the distance from any PP is not given, do we need to take a random distance for drawing the LPP or RPP projections?

if distance is not there then you need to consider object exactly on xy reference line.

fantastic,,it is good way of anlysing figure

please show some examples for RPP and LPP too….it is very necessary…our 1st question is based on it..

Thank u so much it’s really amazing

Thank you so much…really helpful😁

Really Awesome Sir

Helped a lot

Really helpful

really this is awesome..i got clear idea after reading this content…..thank you

Very Nice work and I dont know how to thank u NICE work KEEP it UP

What about a point lying in all the three principle planes.

it will be projected at intersecting point of two reference lines.

Thaks,you have good plan.

awesome…!!!

thank you so much

Very good sir ..greatmy teacher told me to prepare for this topic before he start in class

thanks for thiss sirr.. 🙂

it is so helpful if i got full book pdf