# Problem 4.1 Projection of Points

## Procedure:

Step-1 Draw a horizontal line, which is x-y line of some suitable length.

Step-2 Point P is 25 mm above H.P. and 20 mm behind V.P. So it is in 2nd quadrant and so on a single vertical line above &  from x-y line,  mark a point p’ at the distance 25 mm and point p at the distance 20 mm on it. Point p’ is front view & the point p is top view of the point P.

Step-3 Point Q is 20 mm below H.P. and 25 mm behind V.P, so it is in 3rd quadrant. So draw a vertical line on both sides of the x-y line. On this vertical line, mark a point q’ 20 mm below x-y line and a point q  25 mm above x-y line. Point q’ is front view & the point q is top view of the point Q.

Step-4 Point R is 25 mm below H.P. and 20 mm in front of V.P. So it is in the 4th quadrant. Draw a vertical line below & from x-y line. On this line mark a point r’ at the distance 25 mm and a point r is at the distance 20 mm from x-y line. Point r’ is front view & the point r is top view of the point R.

Step-5 Point S is 20 mm above H.P. and 25 mm in front of V.P. So it is in 1st quadrant. Draw a vertical line on both sides of  the x-y line. On this vertical line, mark a point s’ at the distance 20 mm above the x-y line & a point s at the distance 25 mm below the x-y line. Point s’ is front view & the point s is top view of the point S.

Step-6 Point T is on H.P. and 25 mm in front of V.P. So it is in 1st quadrant but on H.P. Draw a vertical line below & from x-y line. Mark a point t’ on the point of intersection of the x-y line and the previously drawn vertical line & mark a point  t  on the vertical line at the distance 25 mm below x-y line. Point t’ is front view & point t is top view of the point T.

Step-7 Point U is on H.P. and 25 mm behind V.P. So it is 2nd quadrant but on H.P. Draw a vertical line above & from x-y line. Mark a point u’ on the point of intersection of the x-y line and the previously drawn vertical line & mark a point  u  on the vertical line at the distance 25 mm above x-y line. Point u’ is front view & point u is top view of the point U.

Step-8 Point V is on V.P. and 20 mm above H.P. So it is in 1st quadrant but on V.P. Draw a vertical line above & from x-y line. Mark a point v on the point of intersection of the x-y line and the previously drawn vertical line & mark a point  v’ on the vertical line at the distance 20 mm above x-y line. Point v’ is front view & point v is top view of the point V.

Step-9 Point W is on V.P. and 20 mm below H.P. So it is in 4th quadrant but on V.P. Draw a vertical line below & from x-y line. Mark a point w on the point of intersection of the x-y line and the previously drawn vertical line & mark a point w’ on the vertical line at the distance 20 mm below x-y line. Point w’ is front view & point w is top view of the point W.

Step-10 Point X is on H.P. as well as V.P. both. So it is on the x-y line. Mark a point on the x-y line and give the names x’ & x on this same point. Point x’ is front view & point x is top view of the point X.

Step-11 Give the dimensions by any one method of dimensions to all the points as shown into the figure.